You are reading a page from Mathematics of Life Insurance, L. Wayland Downling (1925)
Part of the American Term Life Insurance History Project
Term Life Insurance

                        CONCLVSION
 1. General  Remarks.—The  foregoing  pages  illustrate  the
standard biometric and contingent functions, their relationships,
and their properties in so far as these relate to human life. It
may often happen that the actuary has to deal with more compli-
cated functions than those considered, but the general principles
involved are the same and rest, at bottom, upon the theory of
probability and upon the theory of compound interest.
 
At the same time, the actuary may often have occasion to use
formulas depending upon the theory of large numbers in its
relation to the theory of probability and which do not rest upon
so elementary a basis as do those thus far considered.  A few of
these formulas are added here, more by way of illustrating the
desirability of a knowledge of the calculus than with a view to any
detailed study of them.1
 
Consider, for example, Exercise 3, Sec. 19.  It is clear that the
insurance company will expect to pay, at the end of the first
year, 100 of the 5000 policies issued at age a:.  The expression for
the probability that it will pay exactly 100 of these is
                   
5oooC'loo(0.02)lo°(0.98)4900,
but no one would dream of attempting to compute, by direct
processes, the numerical value of this expression.
 
2. Stirling's Formula.—When an expression, like the above,
involves factorials of large numbers, Stirling's formula will yield
a sufficiently accurate result.  This formula may be written
                       
,      iim  wy^
                     n.   „ = „ —^—,
where e = 2.71828 . . . and v = 3.1416.  The formula will
serve for comparatively small numbers.  Thus, with a seven-place
table of logarithms, the formula gives
 
1 Cf. YOUNG, T. E., "Insurance," Pitman & Sons, where the value
of such formulas is illustrated and emphasized.
                              
106
§3]                            CONCLUSION                           107
               
20! = 2,422,786,000,000,000,000
with an error of less than one-half of 1 per cent.  The approxi-
mation is closer the larger the value of n.
 
3. Probability of Expectation.—With Stirling's formula, the
probability of expectation in re trials, namely,
                      
p = nC'nrCpMg)'".
reduces readily to the simple formula

where

       
1           h                            <«
p =  ,——— = -7='            (1)
   
v2n7rpq   VT
   \/2npq

is a number called the modulus.
 
Thus, in the example just considered

h =

11

\
/2 X 5000 X 0.02 X 0.98I4

and the probability of paying exactly 100 of the 5000 policies at
the end of the first year is thus
               
„ =___= a56419 = 0.0403.
                    14Vr    14
 4. Deviation.—The probability that an event will occur exactly
as many times as expected in a large number of trials is small and
a deviation on one side or the other is quite likely to occur.
 
If r represents the number of times an event is expected to
occur in n trials and ( represents the number of times the event
actually happens, then the number
                          
x = ( -r
is  called the  deviation.   The  deviation is  positive  or negative
according to (> r or « r.  Thus, if there are exactly ninety deaths
among the 5000 policyholders during the first year, the deviation
is -10.
108     MATHEMATICS OF LIFE INSURANCE      [§5
  5. Probability of Deviation.—The probability y that a devia-
tion x will occur in n trials (n being a large number) is given with
sufficient accuracy by the Gaussian error law,
                        y^J-e-^',             (1)
                             VTT
h being the modulus defined in Sec. 3.
  
The graph of Eq. (1) is a normal probability curve.
  The probability of paying exactly ninety of the 5000 policies
the first year is the probability of a deviation of —10 and is,
therefore,
                 
y = -le-l(>%»« = 0.0242.
                      14Vir
  6. Probability of Deviation Lying between Given Limits.—The
probability? that a deviation will occur lying between —a and +a
is given by the formula
   
_h_ f+a ^,  2(ha)r   W  (haV_(haY     -,
"V^-o6   dx~ -v/^L1 ^^Q-V. 7~y.   -J
                      ^ 2(Affl)''y(-lHfea)^
                         \/i^;w(2r+l)r!'
The series in the square brackets converges for all finite values of
ha, and quite rapidly for values of ha less than 1.  For larger
values of ha, the series converges slowly and is not well adapted for
computation.  But for large values of n, h is always small, and
thus Eq. (1) suffices when the limits —a and +a are not far apart.
A table of values of P is inserted in most texts on statistics.
Glover's tables contain a very full table of values.'
 
The probability that the number of deaths among the 5000
policyholders, during the first year, lies between 90 and 110
(limits included) is found by substituting 1 %4 for ha in the above
formula or by making use of a table.  By either method, we find
the required probability to be
                         
P = 0.6876.
 ' The probability integral Eq. (1) is slightly modified in Glover's
tables from the form used here.
§7]                            CONCLUSION                           109
 
7. Probable Deviation.—There are limits  —k and  +k such
that the probability a deviation will fall between them is one-half;
that is, such that a deviation is just as likely to fall between them
as outside them.  With a table of values of P, interpolation gives
hk = 0.47694 when P = ^.  The number
                              
0.47694
                         k = ——,—
is called the probable deviation.
 
The probable deviation in the 5000 policies is
                    k = 0.47694 X 14 = 7
to the nearest integer.  It is an even chance that the number of
deaths will fall between 93 and 107 (limits excluded).
 
8. Mean Deviation.—If  each  possible  deviation,  considered
as a positive number, is multiplied by the probability of its occur-
rence and the products added, the result is called the mean
deviation.
 
The mean deviation is indicated by the Greek letter i\ and is
given by the formula
               
^J-f^e-^dx^———     (1)
                   VirJ-m          h-V-ir
 Thus, in the problem we have been considering,
                r,  =  -14. =  14  X 0.56419  =  8
                     VTT
to the nearest integer.
 
The probability that a deviation will occur between the limits
77 and +T; is found from Eq. (1) Sec. 6 or from a table of values
of P, to be
                         
P = 0.5750.
 9. Standard Deviation.—The standard deviation is indicated
by the Greek letter o- and is given by the formula
               
.T^-^r1"'e-^'xVx^—        W
                     \/vJ-»            ""

or

<r  = ———                                                                (2)
    AV2
110     MATHEMATICS OF LIFE INSURANCE       [§10
  The standard deviation for the 5000 policies is
                     = 14 X 0.7071 = 10
to the nearest integer.
 
The probability that a deviation will fall between —a and +a
is found when ha- = y^ = 0.7071 and is
                        
P = 0.6827.
 The probability that the number of deaths among the 5000
policyholders during the first year will fall between 90 and 110
(limits excluded) is 0.6827 (cf. Sec. 6).
 
10. Recapitulation.—For convenience, the above formulas are
brought together,
     
» = 0               V = —/= = A X 0.56419
                                  VTT
     x = k = a47694        y = J-e-^^ = A x 0.44941
                 h             Va-
     x = n = ,-/=         y = -7=e-V' = h X 0.41038
              A-VTT                VTT
     ^^ATl    2/=^-^= AX 0.34220

+"-^s^

2(fea)''y (-l)^(Aa)2-
VTT ^ (2r + l)r!

r=0

-k < x < +kP= 1

-ri < x < +T,                   P = 0.5750
-o- < x < +0-                 P = 0.6827